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authorPrasanna S. Panchamukhi <prasannax.s.panchamukhi@intel.com>2010-04-13 16:36:26 -0700
committerInaky Perez-Gonzalez <inaky.perez-gonzalez@intel.com>2010-05-11 14:08:58 -0700
commit8a3a1b65eeecd18357ac0cc941f43df153d4f271 (patch)
tree09366a2439b82cc92cd80bb11502c0cb891d2e1d /drivers/net/wimax
parent27502908866ba37d03594e7f7ee7b649cb007330 (diff)
wimax/i2400m: SDIO specific TX queue's minimum buffer room for new message
This patch specifies the TX queue's minimum buffer room required to accommodate one smallest SDIO payload. Please refer the documentation in the code. Signed-off-by: Prasanna S. Panchamukhi <prasannax.s.panchamukhi@intel.com>
Diffstat (limited to 'drivers/net/wimax')
-rw-r--r--drivers/net/wimax/i2400m/sdio.c7
1 files changed, 7 insertions, 0 deletions
diff --git a/drivers/net/wimax/i2400m/sdio.c b/drivers/net/wimax/i2400m/sdio.c
index 7632f80954e..9bfc26e1bc6 100644
--- a/drivers/net/wimax/i2400m/sdio.c
+++ b/drivers/net/wimax/i2400m/sdio.c
@@ -483,6 +483,13 @@ int i2400ms_probe(struct sdio_func *func,
sdio_set_drvdata(func, i2400ms);
i2400m->bus_tx_block_size = I2400MS_BLK_SIZE;
+ /*
+ * Room required in the TX queue for SDIO message to accommodate
+ * a smallest payload while allocating header space is 224 bytes,
+ * which is the smallest message size(the block size 256 bytes)
+ * minus the smallest message header size(32 bytes).
+ */
+ i2400m->bus_tx_room_min = I2400MS_BLK_SIZE - I2400M_PL_ALIGN * 2;
i2400m->bus_pl_size_max = I2400MS_PL_SIZE_MAX;
i2400m->bus_setup = i2400ms_bus_setup;
i2400m->bus_dev_start = i2400ms_bus_dev_start;