diff options
Diffstat (limited to 'Documentation/filesystems')
-rw-r--r-- | Documentation/filesystems/proc.txt | 7 | ||||
-rw-r--r-- | Documentation/filesystems/sharedsubtree.txt | 2 |
2 files changed, 5 insertions, 4 deletions
diff --git a/Documentation/filesystems/proc.txt b/Documentation/filesystems/proc.txt index 264bcde0c51..ddc531a74d0 100644 --- a/Documentation/filesystems/proc.txt +++ b/Documentation/filesystems/proc.txt @@ -234,7 +234,7 @@ Table 1-2: Contents of the status files (as of 2.6.30-rc7) ShdPnd bitmap of shared pending signals for the process SigBlk bitmap of blocked signals SigIgn bitmap of ignored signals - SigCgt bitmap of catched signals + SigCgt bitmap of caught signals CapInh bitmap of inheritable capabilities CapPrm bitmap of permitted capabilities CapEff bitmap of effective capabilities @@ -300,7 +300,7 @@ Table 1-4: Contents of the stat files (as of 2.6.30-rc7) pending bitmap of pending signals blocked bitmap of blocked signals sigign bitmap of ignored signals - sigcatch bitmap of catched signals + sigcatch bitmap of caught signals wchan address where process went to sleep 0 (place holder) 0 (place holder) @@ -854,7 +854,8 @@ WritebackTmp: Memory used by FUSE for temporary writeback buffers if strict overcommit accounting is enabled (mode 2 in 'vm.overcommit_memory'). The CommitLimit is calculated with the following formula: - CommitLimit = ('vm.overcommit_ratio' * Physical RAM) + Swap + CommitLimit = ([total RAM pages] - [total huge TLB pages]) * + overcommit_ratio / 100 + [total swap pages] For example, on a system with 1G of physical RAM and 7G of swap with a `vm.overcommit_ratio` of 30 it would yield a CommitLimit of 7.3G. diff --git a/Documentation/filesystems/sharedsubtree.txt b/Documentation/filesystems/sharedsubtree.txt index 4ede421c968..32a173dd315 100644 --- a/Documentation/filesystems/sharedsubtree.txt +++ b/Documentation/filesystems/sharedsubtree.txt @@ -727,7 +727,7 @@ replicas continue to be exactly same. mkdir -p /tmp/m3 mount --rbind /root /tmp/m3 - I wont' draw the tree..but it has 24 vfsmounts + I won't draw the tree..but it has 24 vfsmounts at step i the number of vfsmounts is V[i] = i*V[i-1]. |