diff options
Diffstat (limited to 'fs/btrfs/inode.c')
| -rw-r--r-- | fs/btrfs/inode.c | 36 |
1 files changed, 31 insertions, 5 deletions
diff --git a/fs/btrfs/inode.c b/fs/btrfs/inode.c index d8393ddc72a..bb7fd807280 100644 --- a/fs/btrfs/inode.c +++ b/fs/btrfs/inode.c @@ -2488,7 +2488,19 @@ static int btrfs_unlink(struct inode *dir, struct dentry *dentry) root = BTRFS_I(dir)->root; + /* + * 5 items for unlink inode + * 1 for orphan + */ + ret = btrfs_reserve_metadata_space(root, 6); + if (ret) + return ret; + trans = btrfs_start_transaction(root, 1); + if (IS_ERR(trans)) { + btrfs_unreserve_metadata_space(root, 6); + return PTR_ERR(trans); + } btrfs_set_trans_block_group(trans, dir); @@ -2503,6 +2515,7 @@ static int btrfs_unlink(struct inode *dir, struct dentry *dentry) nr = trans->blocks_used; btrfs_end_transaction_throttle(trans, root); + btrfs_unreserve_metadata_space(root, 6); btrfs_btree_balance_dirty(root, nr); return ret; } @@ -2583,7 +2596,16 @@ static int btrfs_rmdir(struct inode *dir, struct dentry *dentry) inode->i_ino == BTRFS_FIRST_FREE_OBJECTID) return -ENOTEMPTY; + ret = btrfs_reserve_metadata_space(root, 5); + if (ret) + return ret; + trans = btrfs_start_transaction(root, 1); + if (IS_ERR(trans)) { + btrfs_unreserve_metadata_space(root, 5); + return PTR_ERR(trans); + } + btrfs_set_trans_block_group(trans, dir); if (unlikely(inode->i_ino == BTRFS_EMPTY_SUBVOL_DIR_OBJECTID)) { @@ -2606,6 +2628,7 @@ static int btrfs_rmdir(struct inode *dir, struct dentry *dentry) out: nr = trans->blocks_used; ret = btrfs_end_transaction_throttle(trans, root); + btrfs_unreserve_metadata_space(root, 5); btrfs_btree_balance_dirty(root, nr); if (ret && !err) @@ -5297,11 +5320,14 @@ static int btrfs_rename(struct inode *old_dir, struct dentry *old_dentry, return -ENOTEMPTY; /* - * 2 items for dir items - * 1 item for orphan entry - * 1 item for ref + * We want to reserve the absolute worst case amount of items. So if + * both inodes are subvols and we need to unlink them then that would + * require 4 item modifications, but if they are both normal inodes it + * would require 5 item modifications, so we'll assume their normal + * inodes. So 5 * 2 is 10, plus 1 for the new link, so 11 total items + * should cover the worst case number of items we'll modify. */ - ret = btrfs_reserve_metadata_space(root, 4); + ret = btrfs_reserve_metadata_space(root, 11); if (ret) return ret; @@ -5417,7 +5443,7 @@ out_fail: if (old_inode->i_ino == BTRFS_FIRST_FREE_OBJECTID) up_read(&root->fs_info->subvol_sem); - btrfs_unreserve_metadata_space(root, 4); + btrfs_unreserve_metadata_space(root, 11); return ret; } |